manual: clarify buffer behavior in getline
Commit Message
From: David Svoboda <svoboda@cert.org>
If the user has requested automatic buffer creation, getline may create
it and not free things when an error occurs. That means the user is
always responsible for calling free() regardless of the return value.
The current documentation does not explicitly cover this which leaves it
slightly ambiguous to the reader. So clarify things.
2014-04-02 David Svoboda <svoboda@cert.org>
* manual/stdio.texi (Line-Oriented Input): Document buffer allocation
explicitly.
---
manual/stdio.texi | 3 ++-
1 file changed, 2 insertions(+), 1 deletion(-)
Comments
> If you set @code{*@var{lineptr}} to a null pointer, and @code{*@var{n}}
> to zero, before the call, then @code{getline} allocates the initial
> -buffer for you by calling @code{malloc}.
> +buffer for you by calling @code{malloc}. This buffer remains allocated
Two spaces.
Otherwise fine.
On Thu 03 Apr 2014 10:38:43 Roland McGrath wrote:
> > If you set @code{*@var{lineptr}} to a null pointer, and @code{*@var{n}}
> > to zero, before the call, then @code{getline} allocates the initial
> >
> > -buffer for you by calling @code{malloc}.
> > +buffer for you by calling @code{malloc}. This buffer remains allocated
>
> Two spaces.
>
> Otherwise fine.
fixed & pushed
-mike
@@ -1298,7 +1298,8 @@ back in @code{*@var{n}}.
If you set @code{*@var{lineptr}} to a null pointer, and @code{*@var{n}}
to zero, before the call, then @code{getline} allocates the initial
-buffer for you by calling @code{malloc}.
+buffer for you by calling @code{malloc}. This buffer remains allocated
+even if @code{getline} encounters errors and is unable to read any bytes.
In either case, when @code{getline} returns, @code{*@var{lineptr}} is
a @code{char *} which points to the text of the line.