[committed] d: Update recipes for building html and pdf documentation
Commit Message
Hi,
This patch sorts out the include directories for building the gdc docs -
we don't need to include anything from the toplevel docs directory.
The html output directory has also been renamed from /d/ to /gdc/ to
make it clearer that this is vendor-specific documentation.
Tested by building and checking pdf/info/man/html pages, and committed
to mainline.
Regards,
Iain.
---
gcc/d/ChangeLog:
* Make-lang.in: Only include doc/include when building documentation.
(d.html): Rename html directory to $(build_htmldir)/gdc.
---
gcc/d/Make-lang.in | 15 +++++++--------
1 file changed, 7 insertions(+), 8 deletions(-)
@@ -253,16 +253,15 @@ doc/gdc.info: $(D_TEXI_FILES)
else true; fi
doc/gdc.dvi: $(D_TEXI_FILES)
- $(TEXI2DVI) -I $(abs_docdir) -I $(abs_docdir)/include -o $@ $<
+ $(TEXI2DVI) -I $(abs_docdir)/include -o $@ $<
doc/gdc.pdf: $(D_TEXI_FILES)
- $(TEXI2PDF) -I $(abs_docdir) -I $(abs_docdir)/include -o $@ $<
+ $(TEXI2PDF) -I $(abs_docdir)/include -o $@ $<
-$(build_htmldir)/d/index.html: $(D_TEXI_FILES)
+$(build_htmldir)/gdc/index.html: $(D_TEXI_FILES)
$(mkinstalldirs) $(@D)
rm -f $(@D)/*
- $(TEXI2HTML) -I $(gcc_docdir) -I $(gcc_docdir)/include \
- -I $(srcdir)/d -o $(@D) $<
+ $(TEXI2HTML) -I $(gcc_docdir)/include -I $(srcdir)/d -o $(@D) $<
.INTERMEDIATE: gdc.pod
@@ -277,7 +276,7 @@ d.rest.encap:
d.info: doc/gdc.info
d.dvi: doc/gdc.dvi
d.pdf: doc/gdc.pdf
-d.html: $(build_htmldir)/d/index.html
+d.html: $(build_htmldir)/gdc/index.html
d.srcinfo: doc/gdc.info
-cp -p $^ $(srcdir)/doc
d.srcextra:
@@ -341,10 +340,10 @@ d.install-dvi: doc/gdc.dvi
$(INSTALL_DATA) "$$d$$p" "$(DESTDIR)$(dvidir)/gcc/$$f"; \
done
-d.install-html: $(build_htmldir)/d
+d.install-html: $(build_htmldir)/gdc
@$(NORMAL_INSTALL)
test -z "$(htmldir)" || $(mkinstalldirs) "$(DESTDIR)$(htmldir)"
- @for p in $(build_htmldir)/d; do \
+ @for p in $(build_htmldir)/gdc; do \
if test -f "$$p" || test -d "$$p"; then d=""; else d="$(srcdir)/"; fi; \
f=$(html__strip_dir) \
if test -d "$$d$$p"; then \